Solving Nonlinear Equations

''solve $ f(x) = 0$'' where $ f(x)$ is a function of $ x$. The values of $ x$ that make $ f(x) = 0$ are called the roots of the equation. They are a1so called the zeros of $ f(x)$.
The following non-linear equation can compute the friction factor,$ f$:

$\displaystyle \frac{1}{\sqrt{f}}=\left(\frac{1}{k}\right)ln(RE\sqrt{f)}+\left(14-\frac{5.6}{k}\right)
$

where the parameter $ k$ is known and RE, the so-called Reynold's number. The equation for $ f$ is not solvable except by the numerical procedures of this chapter.

Subsections
2004-12-28