Solving Nonlinear Equations

''solve $f(x) = 0$'' where $f(x)$ is a function of $x$. The values of $x$ that make $f(x) = 0$ are called the roots of the equation. They are a1so called the zeros of $f(x)$.
The following non-linear equation can compute the friction factor,$f$:

\begin{displaymath}
\frac{1}{\sqrt{f}}=\left(\frac{1}{k}\right)ln(RE\sqrt{f)}+\left(14-\frac{5.6}{k}\right)
\end{displaymath}

where the parameter $k$ is known and RE, the so-called Reynold's number. The equation for $f$ is not solvable except by the numerical procedures of this chapter.

Subsections
2004-10-15